Worker

Dina was paid P8.30 per hour and a time-and-a-half for all hours worked in excess of 40 hours per week. She worked 12 hours on Monday, 6 1/2 on Tuesday, 9 on Wednesday,8 on Thursday, and 10 1/2 on Friday. What was her total pay for the week?

Final Answer:

x =  406 ⁷⁄₁₀ = 4067/10

Step-by-step explanation:

$$\begin{gathered} r=8.30 \\ p=r+r/2=8.3+8.3/2=\frac{249}{20}=12\frac{9}{20}=12.45 \\ t=12+6\frac{1}{2}+9+8+10\frac{1}{2}=46\text{h} \\ {t}_1=40\text{h} \\ {t}_2=t-t_1=46-40=6\text{h} \\ x=t_1\cdot r+t_2\cdot p=40\cdot 8.3+6\cdot 12.45=\frac{4067}{10}=406\frac{7}{10}=406.7 \end{gathered}$$

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