Distance 81578

The express train leaves place A at 19:20 and arrives in town B at 20:24. The average speed of the express train is 15 m/s. What is the distance between cities A and B?

Correct answer:

s =  57.6 km

Step-by-step explanation:

v=15 m/s km/h=15 3.6  km/h=54 km/h t1=19:20=19 hr 20 min =19+6020=19.3333 hr19.3333 t2=20:24=20 hr 24 min =20+6024=20.4 hr=20.4  t=t2t1=20.419.3333=15161.0667 h  s=v t=54 1.0667=57.6 km



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