Four-digit eight count

How many four-digit numbers are there in which there are at least three eights

Final Answer:

n =  36

Step-by-step explanation:

8888 [179]888 8[079]88 88[079]8 888[079]  n=1+8+9+9+9=36



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You need to know the following knowledge to solve this word math problem:

combinatoricsbasic operations and conceptsnumbersGrade of the word problem

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