Lighting-650W 82356

In the office will be connected: computer 800W, kettle 2.5KW, lighting-650W, oven 1.9KW; electric stove 3.3KW; air conditioning 6100W. As the smallest cross-section of the cables, we have to bring them to this room. Recalculate for Copper and Aluminum wires.

Correct answer:

S =  6.216 mm2

Step-by-step explanation:

P1=800 W P2=2.5 kW W=2.5 1000  W=2500 W P3=650 W P4=1.9 kW W=1.9 1000  W=1900 W P5=3.3 kW W=3.3 1000  W=3300 W P6=6100 W  P=P1+P2+P3+P4+P5+P6=800+2500+650+1900+3300+6100=15250 W  U=230 V  P = UI  I=P/U=15250/230=23152566.3043 A  S16=1.5 mm2  n=I/16=66.3043/16=36815254.144  S=n S16=4.144 1.5=6.216 mm2



Did you find an error or inaccuracy? Feel free to write us. Thank you!







You need to know the following knowledge to solve this word math problem:

Units of physical quantities:

Themes, topics:

Grade of the word problem:


 
We encourage you to watch this tutorial video on this math problem: video1

Related math problems and questions: