Cable

Cable consists of 8 strands, each strand consists of 12 wires with diameter d = 0.5 mm. Calculate the cross-section of the cable.

Result

S =  18.8 mm2

Solution:

S=812π0.524=18.8 mm2S = 8\cdot 12\cdot \pi \cdot \dfrac{ 0.5^2}{4} = 18.8 \ \text{mm}^2



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