Pipe cross section

The pipe has an outside diameter 1100 mm and the pipe wall is 100 mm thick. Calculate the cross section of this pipe.

Result

S =  6361.725 cm2

Solution:

D=1100 mm r=D/2=1100/2=550 mm T=100 mm r1=r−T=550−100=450 mm S1=π⋅ r12=3.1416⋅ 4502≐636172.5124 mm2 S=S1/102=636172.5124/102≐6361.7251≐6361.725 cm2D=1100 \ \text{mm} \ \\ r=D/2=1100/2=550 \ \text{mm} \ \\ T=100 \ \text{mm} \ \\ r_{1}=r-T=550-100=450 \ \text{mm} \ \\ S_{1}=\pi \cdot \ r_{1}^2=3.1416 \cdot \ 450^2 \doteq 636172.5124 \ \text{mm}^2 \ \\ S=S_{1}/10^2=636172.5124/10^2 \doteq 6361.7251 \doteq 6361.725 \ \text{cm}^2

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