# Again saw

From the trunk of the tree we have to a sculpture beam with rectangular cross-section with dimensions 146 mm and 128 mm. What is the trunk smallest diameter?

Result

D =  194.165 mm

#### Solution:

$D^2 = a^2+b^2 \ \\ D = \sqrt{ 146^2+128^2} = 194.165 \ \text{mm}$

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