Diamond and diagonals

A diamond has diagonals f = 8 cm and g = 6 cm long. How long is this diamond perimeter? (Calculate it!)

Result

o =  20 cm

Solution:

f=8 cm g=6 cm  a=(f/2)2+(g/2)2=(8/2)2+(6/2)2=5 cm o=4⋅ a=4⋅ 5=20=20  cm f = 8 \ cm \ \\ g = 6 \ cm \ \\ \ \\ a = \sqrt{ (f/2)^2+(g/2)^2 } = \sqrt{ (8/2)^2+(6/2)^2 } = 5 \ cm \ \\ o = 4 \cdot \ a = 4 \cdot \ 5 = 20 = 20 \ \text{ cm }

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