Former price

The price of an article is cut by 10℅, to restore it to the former value, by what percent the new price must be increased?

Result

p =  11.111 %

Solution:

 (110/100) (1+p/100)=1  0.9p=10  p=100911.111111 =11.111% \ \\ (1-10/100) \cdot \ (1+p/100)=1 \ \\ \ \\ 0.9p=10 \ \\ \ \\ p=\dfrac{ 100 }{ 9 } \doteq 11.111111 \ \\ =11.111 \%



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