Kilometers 8362

The cyclist left place A at 8:00 a.m. at a constant speed of 25 km/h. At 8:30, a passenger car leaves A at a speed of 75 km/h along the same route. How many kilometers does the cyclist travel before the car catches up with him?

Correct answer:

s =  18.75 km

Step-by-step explanation:


s = 25·(t-8.00)
s = 75 · (t-8.50)

s-25t = -200
s-75t = -637.5

Row 2 - Row 1 → Row 2
s-25t = -200
-50t = -437.5


t = -437.5/-50 = 8.75
s = -200+25t = -200+25 · 8.75 = 18.75

s = 75/4 = 18.75
t = 35/4 = 8.75

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