Cyclist Car Catch Distance

The cyclist left place A at 8:00 a.m. at a constant speed of 25 km/h. At 8:30, a passenger car leaves A at a speed of 75 km/h along the same route. How many kilometers does the cyclist travel before the car catches up with him?

Final Answer:

s =  18.75 km

Step-by-step explanation:

v1=25 km/h v2=75 km/h  s = v1 (t8.00) s = v2   (t8.50)  v1 (t8.00)=v2 (t8.50) 25 (t8.00)=75 (t8.50)  50t=437.5  t=50437.5=8.75  t=435=8.75  s=v1 (t8.00)=25 (8.758.00)=18.75 km



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