The common difference 2

Find the common difference of an arithmetic progression (AP), whose first term is 5 and sum of its first 4 terms is half the sum of the next four terms.

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Dr Math
Another solution:

first term is 5
sum of its first 4 terms is half the sum of the next four terms.
Let the common difference between d
Sn = n/2 (2a + (n - 1)d)
S4=4/2(2*5+(4-1)d)
=2(10+3d)=20+6d
S8-S4=8/2(2*5+7d)-20-6d
=(40+28d-20-6d)
=(20+22d)
As per question,
(20+6d)*2=20+22d
=>40+12d=20+22d
=>10d=20
=>d=2

S4=20+6d =20+6(2)=32
S8-S4=20+22d=20+44=64





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