Kites

Boys run kite on a cable of 68 meters long. What is the kite altitude, if the angle from the horizontal plane is 72°?

Result

h =  65 m

Solution:

l=68 m sin⁡A=h:l  h=l⋅ sin⁡(72∘→ rad)=l⋅ sin⁡(72∘⋅ π180 )=68⋅ sin⁡(72∘⋅ 3.1415926180 )=64.67184=65 ml=68 \ \text{m} \ \\ \sin A=h:l \ \\ \ \\ h=l \cdot \ \sin( 72 ^\circ \rightarrow\ \text{rad} )=l \cdot \ \sin( 72 ^\circ \cdot \ \dfrac{ \pi }{ 180 } \ )=68 \cdot \ \sin( 72 ^\circ \cdot \ \dfrac{ 3.1415926 }{ 180 } \ )=64.67184=65 \ \text{m}

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