Shear friction

How much force must be applied to a box weighing 300 kg to move it at a constant speed along a horizontal floor, if the coefficient of sliding friction between the box and the floor is 0.5?

Final Answer:

F =  1500 N

Step-by-step explanation:

m=300 kg g=10 m/s2 k=0.5  F1=m g=300 10=3000 N  F=k F1=0.5 3000=1500 N



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