Coefficient 70214

An 80 kg cart moving at constant speed along a horizontal road is subjected to a pulling force of 120 N.
Specify:
a) the magnitude of the frictional force
b) the value of the coefficient of shear friction.

Correct answer:

F2 =  120 N
k =  0.1529

Step-by-step explanation:

m=80 kg g=9.81 m/s2 F1=120 N  F2=F1=120=120 N
G=m g=80 9.81=53924=78454=784.8 N  F2 = k G  k=F2/G=120/784.8=0.1529



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