Friction coefficient

What is the weight of a car when it moves on a horizontal road at a speed of v = 50 km/h at engine power P = 7 kW? The friction coefficient is 0.07

Result

m =  720 kg

Solution:

v=50 km/h=50/3.6 m/s=13.88889 m/s P=7000 W t=0.07 g=10 m/s2  P=Fv  F=P/v=7000/13.8889=504 N  F=tmg  m=F/(t⋅ g)=504/(0.07⋅ 10)=720 kgv=50 \ km/h=50 / 3.6 \ m/s=13.88889 \ m/s \ \\ P=7000 \ \text{W} \ \\ t=0.07 \ \\ g=10 \ \text{m/s}^2 \ \\ \ \\ P=Fv \ \\ \ \\ F=P/v=7000/13.8889=504 \ \text{N} \ \\ \ \\ F=t m g \ \\ \ \\ m=F/(t \cdot \ g)=504/(0.07 \cdot \ 10)=720 \ \text{kg}

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