Engine performance

The car's engine develops a power of 1800N. Find its performance if it travels evenly on a horizontal path at 48 km/h.

Final Answer:

P =  24 kW

Step-by-step explanation:

F=1800 N v=48 km/h m/s=48:3.6  m/s=13.33333 m/s  W = F s v = s/t  P = W/t =  tF s  =  tF v t   P1=F v=1800 13.3333=24000 W  P=@P1 kW=P1:1000  kW=24000:1000  kW=24 kW=24 kW



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