Brakes of a car

For the brakes of a passenger car to be effective, it is prescribed that a car moving on a horizontal road at a speed of 40 km. A car must stop on the track 15.4 m. What is the deceleration of the car?

Correct result:

a =  4.0083 m/s2

Solution:

v=40 km/h m/s=40/3.6  m/s=11.11111 m/s s=15.4 m  s=12at2  v=at s=12a(v/a)2  2 s=v2/a  a=v2/(2 s)=11.11112/(2 15.4)=4.0083 m/s2



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