Braking distance

The car travels at an average speed of 12 km/h and detects an obstacle 10 m in front of it. At 1 m in front of the obstacle it already runs 2 km/h. What is the braking distance? What is the required deceleration for stop in:

A) 1m
B) 1s?

Correct answer:

x =  12.96 m
a₂ =  0.5556 m/s²

Step-by-step explanation:

$$\begin{gathered} t_2=2\cdot s_1\mathrm{/}(v_1-0)=2\cdot 10\mathrm{/}(3.3333-0)=6\text{ s } \\ {a}_2={\displaystyle \frac{v_1}{t_2}}={\displaystyle \frac{3.3333}{6}}={\displaystyle \frac{5}{9}}=0.5556{\text{m/s}}^2 \end{gathered}$$

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