The car driver drives at a speed of 100 km/h, saw the obstacle, and began to brake with a slowing of 5 m/s². What is the length of the pathway to stopping the car when the driver has registered the obstacle with a delay of 0.7 s?

Correct answer:

s =  96.6049 m

Step-by-step explanation:

v=100 km/h m/s=100:3.6  m/s=27.77778 m/s a=5 m/s2 d=0.7 s  s0=v d=27.7778 0.7=917519.4444  t=v/a=27.7778/5=9505.5556 s  s1=21 a t2=21 5 5.55562=81625077.1605 m  s=s0+s1=19.4444+77.1605=817825 m=96.6049 m

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