Traveling 82597

What constant braking force is required to stop a car weighing 1 ton in 10 seconds traveling at 50 km/h?

Correct answer:

F =  1.3889 kN

Step-by-step explanation:

m=1 t kg=1 1000  kg=1000 kg t=10 s v=50 km/h m/s=50:3.6  m/s=13.88889 m/s  a=v/t=13.8889/10=18251.3889 m/s2  F1=m a=1000 1.3889=9125001388.8889 N  F=F1/1000=1388.8889/1000=1.3889 kN



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