The braking efficiency of a passenger car is required to stop at 12.5 m at an initial speed of 40 km/h. What is the acceleration braking by brakes?

Correct answer:

a =  -4.9383 m/s2

Step-by-step explanation:

v1=40 km/h m/s=40:3.6  m/s=11.11111 m/s v2=0 m/s  s=12.5 m v=2v1+v2=211.1111+0=9505.5556 m/s  t=s/v=12.5/5.5556=49=2.25 s  a=tv2v1=2.25011.1111=81400 m/s2=4.9383 m/s2

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