A passenger car and an ambulance come to the rectangular crossroad, the ambulance left. Passenger car at speed 39 km/h and ambulance at 41 km/h.

Calculate such a relative speed of the ambulance move to the car.

Correct answer:

v =  56.59 km/h

Step-by-step explanation:

v1=39 km/h v2=41 km/h  s2=s12+s22 (vt)2=(v1 t)2+(v2 t)2  v2=v12+v22  v=v12+v22=392+412=3202=56.59 km/h

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