A passenger car and an ambulance come to the rectangular crossroad, and the ambulance leaves. Passenger car at speed 39 km/h and ambulance at 41 km/h.

Calculate the relative speed of the ambulance moving to the car.

Correct answer:

v =  56.59 km/h

Step-by-step explanation:

v1=39 km/h v2=41 km/h  s2 = s12 + s22 (vt)2 = (v1 t)2 + (v2 t)2  v2 = v12+v22  v=v12+v22=392+412=3202=56.59 km/h

Did you find an error or inaccuracy? Feel free to write us. Thank you!

Showing 1 comment:
Math student
dont understand

Tips for related online calculators
Our vector sum calculator can add two vectors given by their magnitudes and by included angle.
Do you want to convert velocity (speed) units?
See also our right triangle calculator.
See also our trigonometric triangle calculator.

We encourage you to watch this tutorial video on this math problem: video1   video2

Related math problems and questions: