Motor physics

Car traveling at 130 km/h on the highway. Pulling power of the motor is 8 kN.

Determine engine power in kW.

Result

P =  288.9 kW

Solution:

v=130 km/h=36.11 m/s F=8 kN  W=Fs P=W/t=Fs/t=Fv P=8⋅36.11=288.9 kWv = 130 \ km/h = 36.11 \ m/s \ \\ F = 8 \ kN \ \\ \ \\ W = Fs \ \\ P = W/t = Fs/t = Fv \ \\ P = 8 \cdot 36.11 = 288.9 \ \text{kW}

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