At what horizontal distance reaches the car weight m = 753 kg speed v = 74 km/h when the car engine develops a tensile force F = 3061 N. (Neglect resistance of the environment.)

Correct result:

x =  52 m


m=753 kg v=74 km/h m/s=74/3.6  m/s=20.55556 m/s F=3061 N  F=ma a=F/m=3061/753=30617534.0651 m/s2  v=at t=v/a=20.5556/4.06515.0566 s  x=12 a t2=12 4.0651 5.05662=52 m

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