The car

The car weight 1280 kg, increased its speed from 7.3 m/s to 63 km/h on a track of 37.2 m. What force did the car engine have to exert?

Correct answer:

F =  4352 N

Step-by-step explanation:

m=1280 kg v1=7.3 m/s v2=63 km/h m/s=63:3.6  m/s=17.5 m/s s=37.2 m  s=v1 t+21 a t2 v2=v1+a t v2v1=at  s=v1 t+21 (v2v1) t  t=2 v1+v2v12 s  t=v1+v22 s=7.3+17.52 37.2=3 s  a=tv2v1=317.57.3=517=3.4 m/s2  F=m a=1280 3.4=4352=4352 N   Verifying Solution:   s2=v1 t+21 a t2=7.3 3+21 3.4 32=5186=37.2 m



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