The car

The car weight 1280 kg and increased its speed from 7.3 m/s to 63 km/h on a track of 37.2 m. What force did the car engine have to exert?

Correct answer:

F =  4352 N

Step-by-step explanation:

m=1280 kg v1=7.3 m/s v2=63 km/h m/s=63:3.6  m/s=17.5 m/s s=37.2 m  s = v1 t + 21  a   t2 v2 = v1 + a t v2v1 = at  s = v1 t + 21  (v2v1)   t  t =  2 v1 + v2v12 s  t=v1+v22 s=7.3+17.52 37.2=3 s  a=tv2v1=317.57.3=517=3.4 m/s2  F=m a=1280 517=51280 17=521760=4352=4352 N   Verifying Solution:   s2=v1 t+21 a t2=7.3 3+21 3.4 32=5186=37.2 m

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