Coefficient 81094

A car moves along a horizontal road at a speed of 15 m/s. After turning off the engine, the car traveled a distance of 225 m. What was the coefficient of friction for this motion?

Correct answer:

x =  0.05

Step-by-step explanation:

v=15 m/s s=225 m g=10 m/s2  v = a t s = 21 a t2 s = 21 v t  t=2 s/v=2 225/15=30 s a=2 s/t2=2 225/302=21=0.5 m/s2  F = x m g = m a  x g = a x=a/g=0.5/10=201=0.05

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