Coefficient 45821

What is the smallest radius a turn must-have for a car to enter safely without exceeding a speed of 50 km/h? The coefficient of shear friction between the tires and the surface is 0.4.

Correct answer:

r =  7.8655 m

Step-by-step explanation:

v=50 km/h m/s=50:3.6  m/s=13.88889 m/s g=9.81 m/s2 k=0.4  Fg = mg Fo = m v2 / r  Fo k = Fg m v2 / r k = m g  v2 / r k = g  r=gv2 k=9.8113.88892 0.4=7.8655 m



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