Equality of Moments

A lever with a mass of 3 kg and a length of 2 m is loaded at the end with weights with masses of 5 kg and 8 kg.
Find the place where the lever must be supported so that it is in balance.

Correct answer:

x =  1.3 m

Step-by-step explanation:

m1=5 kg m2=8 kg m0=3 kg L=2 m  x+y = L M1=M2  x+y=L m1 x + m0 (L/2x) = m2 y  m1 x+m0 (L/2x)=m2 (Lx) 5 x+3 (2/2x)=8 (2x)  20x=26  x=2026=1.3  x=1013=1.3=1.3 m



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