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An 8-meter-long swing is supported at the center. A 30 kg boy is sitting at one end. How far from the axis of rotation on the other side of the swing must the second boy of mass 40 kg sit?

Correct answer:

x =  3 m

Step-by-step explanation:

m1=30 kg m2=40 kg l=8 m l1=l/2=8/2=4 m  M1=M2 m1 l1 = m2   x  x=m2m1 l1=4030 4=4030 4=40120=3 m



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