The swing

To swing the two girls. Aneta weight 45 kg and Simon 35 kg weight. How far should sit Simon from the middle of swing so it is balanced, if we know that Aneta is sitting at distance 1,5m? How far are girls sitting apart?

Result

r2 =  1.929 m
x =  3.429 m

Solution:

m1=45 m2=35 r1=1.5 M1=M2 m1 gr1=m2 gr2 r2=m1 r1/m2=45 1.5/3527141.92861.929 mm_{1}=45 \ \\ m_{2}=35 \ \\ r_{1}=1.5 \ \\ M_{1}=M_{2} \ \\ m_{1} \ g r_{1}=m_{2} \ g r_{2} \ \\ r_{2}=m_{1} \cdot \ r_{1}/m_{2}=45 \cdot \ 1.5/35 \doteq \dfrac{ 27 }{ 14 } \doteq 1.9286 \doteq 1.929 \ \text{m}
x=r1+r2=1.5+1.9286=3.429 mx=r_{1}+r_{2}=1.5+1.9286=3.429 \ \text{m}



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