# The second

The second angle of a triangle is the same size as the first angle. The third angle is 12 degrees larger than the first angle. How large are the angles?

Result

A =  56 °
B =  56 °
C =  68 °

#### Solution:

$A+B+C=180 \ \\ A=B \ \\ C=12 + A \ \\ \ \\ A + A + (12+A)=180 \ \\ \ \\ 3A=168 \ \\ \ \\ A=56 \ \\ =56 ^\circ$
$B=A=56=56 ^\circ$
$C=12+A=12+56=68=68 ^\circ$

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