# Copper sulphate

How much g of water do we have to add to 240 g of an 84% CuSO4 solution to produce a 60% solution? (Express the mass of crystalline CuSO4 in the original solution and in the resulting solution and compare them. )

Result

w =  96 g
m1 =  201.6 g
m2 =  201.6 g

#### Solution:

0.84*240 = 0.60 *(240+w)

0.6w = 57.6

w = 96

Calculated by our simple equation calculator.
$m_{1}=0.84 \cdot \ 240=201.6=\dfrac{ 1008 }{ 5 }=201.6 \ \text{g}$
$m_{2}=0.60 \cdot \ (240+w)=0.60 \cdot \ (240+96)=\dfrac{ 1008 }{ 5 }=201.6 \ \text{g} \ \\ \ \\ m_{1}=m_{2}$

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