Probability 9771

What is the probability that ten molecules will arrange within the brown motion to be one molecule in the lower half and nine molecules in the upper half in one vessel?

Correct answer:

p =  0.0098

Step-by-step explanation:

$$\begin{gathered} q=0.5 \\ {C}_1(10)=\left(\genfrac{}{}{0ex}{}{10}{1}\right)=\frac{10!}{1!(10-1)!}=\frac{10}{1}=10 \\ p=\left(\genfrac{}{}{0ex}{}{10}{1}\right)\cdot q^1\cdot (1-q{)}^9=10\cdot 0.5^1\cdot (1-0.5{)}^9=0.0098 \end{gathered}$$

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