AP - simple

Find the first ten members of the sequence if a11 = 132, d = 3.

Result

a10 =  129
a9 =  126
a8 =  123
a7 =  120
a6 =  117
a5 =  114
a4 =  111
a3 =  108
a2 =  105
a1 =  102

Solution:

Solution in text a__10 =
Solution in text a__9 =
Solution in text a__8 =
Solution in text a__7 =
Solution in text a__6 =
Solution in text a__5 =
Solution in text a__4 =
Solution in text a__3 =
Solution in text a__2 =
Solution in text a__1 =







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