Computer revolution

When we started playing with computers, the first processor, which I remember was the Intel 8080 from 1974, with the performance of 0.5 MIPS.


Calculate how much percent of a year rose CPU performance when Intel 486DX from 1992 has 54 MIPS.


What would be the consumption of a normal car now (2018) if consumption declined at the same rate from 10 liters per 100 km (round to 3 decimal places)?

Final Answer:

p₂ =  61.9906 %
Q₂ =  0 l

Step-by-step explanation:

$$\begin{gathered} y=1992-1974=18 \\ n=54/0.5=108 \\ n=q^y \\ \ln ny\cdot \ln q \\ q=\frac{\ln n}{\ln y}=\frac{\ln 108}{\ln 18}\doteq 1.6199 \\ q=1+p_2/100 \\ {p}_2=100\cdot (q-1)=100\cdot (1.6199-1)=61.9906\% \end{gathered}$$

$$\begin{gathered} Q_1=10.0\text{l/}1 \\ {n}_2=q^{2018-1974}=1.6199^{2018-1974}\doteq 1650268341.3116 \\ {Q}_2=Q_1/n_2=10/1650268341.3116=0\text{l} \end{gathered}$$

Try another example