Three metal balls with volumes V1=71 cm3 V2=78 cm3 and V3=64 cm3 melted into one ball. Determine it's surface area.

Correct answer:

S =  172.5 cm2

Step-by-step explanation:

V=V1+V2+V3=213 cm3 V=34πr3=213 cm3 r=34π3V=3.7 cm  S=4πr2=4π3.72=172.5 cm2

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