Cylinder melted into cuboid

A circular cylinder has area of cross section 56cm2 and the height is 10cm the cylinder is melted and made into a cuboid of base area 16cm2. What is the height of the cuboid?

Result

h =  35 cm

Solution:

$S_{ 1 }=56 \ \text{cm}^2 \ \\ S_{ 2 }=16 \ \text{cm}^2 \ \\ h_{ 1 }=10 \ \text{cm} \ \\ \ \\ h=\dfrac{ S_{ 1 } }{ S_{ 2 } } \cdot \ h_{ 1 }=\dfrac{ 56 }{ 16 } \cdot \ 10=35 \ \text{cm}$

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