Cylinder-shaped 4411

A cylinder-shaped hole with a diameter of 12 cm is drilled into a block of height 50 cm with a square base with an edge length of 20 cm. The axis of this opening passes through the center of the base of the cuboid. Calculate the volume and surface area of ​​the resulting body.

Correct answer:

V =  14345.1332 cm3
S =  6458.7609 cm2

Step-by-step explanation:

h=50 a=20 P1=a2=202=400 V1=P1 h=400 50=20000 D=12 r=D/2=12/2=6 P2=π r2=3.1416 62113.0973 V2=P2 h=113.0973 505654.8668 V=V1V2=200005654.8668=14345.1332 cm3=1.435104 cm3
S2=4 a h+2 P1=4 20 50+2 400=4800 S3=π D h=3.1416 12 501884.9556 S=S2+S32 P2=4800+1884.95562 113.0973=6458.7609 cm2



Did you find an error or inaccuracy? Feel free to write us. Thank you!







You need to know the following knowledge to solve this word math problem:


 
We encourage you to watch this tutorial video on this math problem: video1

Related math problems and questions: