Cylinder-shaped 4411

A cylinder-shaped hole with a diameter of 12 cm is drilled into a block of height 50 cm with a square base with an edge length of 20 cm. The axis of this opening passes through the center of the base of the cuboid. Calculate the volume and surface area of ​​the resulting body.

Correct answer:

V =  14345.1 cm3
S =  6458.8 cm2

Step-by-step explanation:

h=50 cm a=20 cm  P1=a2=202=400 cm2 V1=P1 h=400 50=20000 cm3  D=12 cm r=D/2=12/2=6 cm  P2=π r2=3.1416 62113.0973 cm2 V2=P2 h=113.0973 505654.8668 cm3  V=V1V2=200005654.8668=14345.1 cm3
S2=4 a h+2 P1=4 20 50+2 400=4800 cm2 S3=π D h=3.1416 12 501884.9556 cm2  S=S2+S32 P2=4800+1884.95562 113.0973=6458.8 cm2

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