The ladder has a length of 3 m and is leaning against the wall, and its inclination to the wall is 45°. How high does it reach?

Correct result:

h =  2.121 m

Solution:

$A=45 \ ^\circ \ \\ B=90 - A=90 - 45=45 \ ^\circ \ \\ c=3 \ \text{m} \ \\ \ \\ \sin B=h:c \ \\ \ \\ h=c \cdot \ \sin B \ \\ \ \\ h=c / \sqrt{ 2 }=3 / \sqrt{ 2 }=2.121 \ \text{m}$

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