# Squares

From a square of 12 dm perimeter is cut smaller square, whose side is the third side of the square. What is the area of the rest?

Result

S =  8 dm2

#### Solution:

$o=12 \ \text{dm} \ \\ a=o/4=12/4=3 \ \text{dm} \ \\ \ \\ a_{2}=a/3=3/3=1 \ \text{dm} \ \\ \ \\ S_{1}=a^2=3^2=9 \ \text{dm}^2 \ \\ S_{2}=a_{2}^2=1^2=1 \ \text{dm}^2 \ \\ \ \\ S=S_{1}-S_{2}=9-1=8 \ \text{dm}^2$

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