Train

The train is running at speeds of 96 km/h. From the beginning of braking to full stop train run for 3.3 minutes. If the train slows the braking equally, calculate the distance of the place from the station where you need to start to brake.

Result

s =  2640 m

Solution:

t=3.3 min=198 s a=ΔvΔt=96/3.6 m/s3.360 s=0.1347 m/s2  s=12at2=120.13471982=2640 mt = 3.3 \ min = 198 \ s \ \\ a = \dfrac{ \Delta v}{\Delta t} = \dfrac{ 96/3.6 \ m/s }{ 3.3 \cdot 60 \ s } = 0.1347 \ m/s^2 \ \\ \ \\ s = \dfrac12 a t^2 = \dfrac12 \cdot 0.1347 \cdot 198^2 = 2640 \ \text{m}



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