Center of gravity

The mass points are distributed in space as follows - specify by coordinates and weight. Find the center of gravity of the mass points system:

A1 [1; -20; 3] m1 = 46 kg
A2 [-20; 2; 9] m2 = 81 kg
A3 [9; -2; -10] m3 = 59 kg
A4 [3; 18; -14] m4 = 91 kg
A5 [6; -12; -19] m5 = 48 kg
A6 [5; 4; -18] m6 = 72 kg
A7 [-14; 3; 19] m7 = 21 kg


Correct result:

x0 =  -0.9952
y0 =  1.2847
z0 =  -6.7129

Solution:

x1=1;y1=20;z1=3 m1=46 x2=20;y2=2;z2=9 m2=81 x3=9;y3=2;z3=10 m3=59 x4=3;y4=18;z4=14 m4=91 x5=6;y5=12;z5=19 m5=48 x6=5;y6=4;z6=18 m6=72 x7=14;y7=3;z7=19 m7=21 m=m1+m2+m3+m4+m5+m6+m7=46+81+59+91+48+72+21=418  Mx=m1 x1+m2 x2+m3 x3+m4 x4+m5 x5+m6 x6+m7 x7=46 1+81 (20)+59 9+91 3+48 6+72 5+21 (14)=416  My=m1 y1+m2 y2+m3 y3+m4 y4+m5 y5+m6 y6+m7 y7=46 (20)+81 2+59 (2)+91 18+48 (12)+72 4+21 3=537  Mz=m1 z1+m2 z2+m3 z3+m4 z4+m5 z5+m6 z6+m7 z7=46 3+81 9+59 (10)+91 (14)+48 (19)+72 (18)+21 19=2806  x0=Mxm=(416)418=208209=0.9952
y0=Mym=537418=1.2847
z0=Mzm=(2806)418=1403209=6.7129



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