Trapezoid ABCD

Calculate the perimeter of trapezoid ABCD if we know the side c=15, b=19 which is also a height and side d=20.

Result

x =  75.245 cm

Solution:

$b=19 \ \\ c=15 \ \\ d=20 \ \\ a_{1}=\sqrt{ d^2-b^2 }=\sqrt{ 20^2-19^2 } \doteq \sqrt{ 39 } \doteq 6.245 \ \\ a=c + a_{1}=15 + 6.245 \doteq 21.245 \ \\ x=a+b+c+d=21.245+19+15+20 \doteq 75.245 \doteq 75.245 \ \text{cm}$

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