Sum-log

The sum of two numbers is 32, the sum of their logarithms (base 10) is 2.2. Determine these numbers.

Correct result:

x =  25.8747
y =  6.1253

Solution:

x+y=32 logx+logy=2.2  y=32y  logxy=2.2 xy=102.2  x(32x)=102.2 32xx2102.2=0 x232x+158.4893=0  x1,2=b±D2a=32±390.042 x1,2=16±9.87474965525 x1=25.8747496553 x2=6.12525034475
y=((32)(19.7494993105))/(2 (1))=6.1253



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