Sphere A2V

Surface of the sphere is 241 mm2. What is its volume?

Result

V =  351.803 mm3

Solution:

S=241 mm2 S=4π r2  r=S4π=2414 3.14164.3793 mm  V=43 π r3=43 3.1416 4.37933351.8029=351.803 mm3S = 241 \ mm^2 \ \\ S = 4 \pi \cdot \ r^2 \ \\ \ \\ r = \sqrt{ \dfrac{ S }{ 4 \pi } } = \sqrt{ \dfrac{ 241 }{ 4 \cdot \ 3.1416 } } \doteq 4.3793 \ mm \ \\ \ \\ V = \dfrac{ 4 }{ 3 } \cdot \ \pi \cdot \ r^3 = \dfrac{ 4 }{ 3 } \cdot \ 3.1416 \cdot \ 4.3793^3 \doteq 351.8029 = 351.803 \ mm^3







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