Perimeter of the garden

The length of the garden measures 27 1/4m. How many meters is this dimension larger than the width of the garden, which measures 15 1/2 m? Calculate the perimeter of the garden.

Final Answer:

d =  11 ³⁄₄ = 47/4 m
o =  85 ¹⁄₂ = 171/2 m

Step-by-step explanation:

$$\begin{gathered} a=27\frac{1}{4}=27+\frac{1}{4}=\frac{27\cdot 4+1}{4}=\frac{108+1}{4}=\frac{109}{4}=27.25\text{m} \\ b=15\frac{1}{2}=15+\frac{1}{2}=\frac{15\cdot 2+1}{2}=\frac{30+1}{2}=\frac{31}{2}=15.5\text{m} \\ d=a-b=\frac{109}{4}-\frac{31}{2}=\frac{109}{4}-\frac{62}{4}=\frac{109-62}{4}=\frac{47}{4}=\frac{47}{4}\text{m}=11\frac{3}{4}\text{m}=11.75\text{m} \end{gathered}$$

$o=2\cdot (a+b)=2\cdot (\frac{109}{4}+\frac{31}{2})=\frac{171}{2}\text{m}=85.5\text{m}$

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