# Chords

How many 4-tones chords (chord = at the same time sounding different tones) is possible to play within 7 tones?

Correct result:

n =  35

#### Solution:

$n={C}_{4}\left(7\right)=\left(\genfrac{}{}{0px}{}{7}{4}\right)=\frac{7!}{4!\left(7-4\right)!}=\frac{7\cdot 6\cdot 5}{3\cdot 2\cdot 1}=35$

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