Circles

In the circle with a radius 7.5 cm are constructed two parallel chord whose lengths are 9 cm and 12 cm. Calculate the distance of these chords (if there are two possible solutions write both).

Correct result:

x =  10.5 cm
y =  1.5 cm

Solution:

$$\begin{gathered} r^2=7.5^2=x_1^2+(9\mathrm{/}2{)}^2 \\ {r}^2=7.5^2=x_2^2+(12\mathrm{/}2{)}^2 \\ {x}_1=6cm \\ {x}_2=4.5cm \\ x=x_1+x_2=10.5\text{ cm} \end{gathered}$$

$y=\mathrm{\mid }{x}_1-x_2\mathrm{\mid }=1.5\text{ cm}$

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