RT 11

Calculate the area of right tirangle if its perimeter is p = 45 m and one cathethus is 20 m long.

Correct result:

S =  45 m2

Solution:

b=20 c2=a2+b2 45=a+b+c S=12ab  45=a+b+a2+b2 45=a+20+a2+202 25=a+a2+400 25−a=a2+400 625−50a+a2=a2+400 625−50a=400 625−400=50a  a=(625−400)/50=4.5   S=12ab=12⋅4.5⋅20=45 m2

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