Triangle

Calculate the triangle sides if its area S = 630 and the second leg is shorter by 17.

Final Answer:

a =  45
b =  28
c =  53

Step-by-step explanation:

S=630 b=a−17  S = 2ab​ =  2a(a−17)​ = 630  a(a−17)=2⋅ 630  a(a−17)=2⋅ 630 a2−17a−1260=0  p=1;q=−17;r=−1260 D=q2−4pr=172−4⋅1⋅(−1260)=5329 D>0  a1,2​=2p−q±D​​=217±5329​​ a1,2​=217±73​ a1,2​=8.5±36.5 a1​=45 a2​=−28  a=a1​=45

Our quadratic equation calculator calculates it.

b=a−17=45−17=28
c=a2+b2​=452+282​=53

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You need to know the following knowledge to solve this word math problem:

algebraarithmeticplanimetricsUnits of physical quantitiesGrade of the word problem

 
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